March Madness - Entry 6

Couldn't finish the IRC bot (with responses) so I did a Project Euler problem to fill the time. Hmph!

The sum of the squares of the first ten natural numbers is,

1² + 2² + ... + 10² = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)² = 55² = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025  385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

values = range(1, 100 + 1, 1)

sumSquares = 0
for i in range(0, 100, 1):
    sumSquares += values[i]**2
squareSums = sum(values)**2

print squareSums - sumSquares

Really simple. The result? 25,164,150.